General & Organic Chemistry
ChemistryLesson 1 of 3
Stoichiometry, Moles & Concentration Calculations
100%
Hold ⌘ / Ctrl and scroll to zoom
SubjectLessonDone
Drag to pan · ⌘/Ctrl + scroll or pinch to zoom · tap a node for detail · +/− to expand a branch
Stoichiometry measures quantitative relationships between reactants and products in chemical reactions.
Mole Formula: n=\frac{m}{M}
- Molarity (M): M = \frac{n_{\text{solute}}}{V_{\text{solution} (L)}}.
- Avogadro's Number: N = n \cdot N_A where N_A = 6.022 \times 10^{23} \text{ mol}^{-1}.
- Dilution Law: M_1 V_1 = M_2 V_2 (moles of solute remain constant before and after dilution).
- Percentage Yield: \text{Yield \%} = \frac{\text{Actual Yield}}{\text{Theoretical Yield}} \times 100.
Step-by-Step Problem Solving: 1. Convert mass of reactants to moles using molar mass: n = m / M. 2. Balance the chemical reaction equation. 3. Divide moles by coefficients to identify the limiting reagent. 4. Calculate theoretical product yield based strictly on the limiting reagent.
Exam strategy
Focus on understanding underlying concepts — exam questions test application, not memorization.
Unlock AI tutoring for this exam →