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Questo esame si sostiene in inglese: le lezioni e le domande sono in inglese. L'interfaccia resta in italiano.
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Part 1 of 4
Uniformly accelerated linear motion obeys the fundamental kinematics equations: v = v_0 + at, s = v_0 t + 0.5 a t^2, and v^2 = v_0^2 + 2as. Newton's Second Law states that the net force acting on a body equals mass times acceleration: F_net = m * a.
Work done by a constant force is defined as W = F * d * cos(theta). The work-energy theorem connects net work directly to changes in kinetic energy: W_net = Delta E_k = 0.5 m v^2 - 0.5 m v_0^2. Gravitational potential energy near Earth's surface is E_p = m g h.
Worked example
A 4.0 kg object accelerates from rest at a = 3.0 m/s^2 over a distance of d = 6.0 m. Find final velocity, net force, and work done. Net force F = m*a = 4.0 * 3.0 = 12 N. Final velocity v^2 = 0 + 2(3.0)(6.0) = 36 implies v = 6.0 m/s. Work W = F*d = 12 * 6.0 = 72 J (equal to final E_k = 0.5 * 4.0 * 6.0^2 = 72 J).
1.Newton's Second Law states that net force acting on a body equals m * a.
2.Kinetic energy of a body is directly proportional to its velocity.
3.Free-fall distance from rest under constant acceleration g is s = 0.5 g t^2.
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